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Question 34 — JEE (Main) 24 Jan 2023 S Ii

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  • #11835
    Om Sharma
    Keymaster

    The value of $\left(\frac{1+\sin \frac{2 \pi}{9}+\mathrm{i} \cos \frac{2 \pi}{9}}{1+\sin \frac{2 \pi}{9}-\mathrm{i} \cos \frac{2 \pi}{9}}\right)^{3}$ is [JEE (Main) 24 Jan 2023 S II]
    (A) $\frac{1}{2}(1-\mathrm{i} \sqrt{3})$
    (B) $-\frac{1}{2}(\sqrt{3}-\mathrm{i})$
    (C) $-\frac{1}{2}(1-\mathrm{i} \sqrt{3})$
    (D) $\frac{1}{2}(\sqrt{3}+\mathrm{i})$

    #11836
    Om Sharma
    Keymaster

    Solution

    Let $\sin \frac{2 \pi}{9}+\mathrm{i} \cos \frac{2 \pi}{9}=\mathrm{z} \Rightarrow\left(\frac{1+\mathrm{z}}{1+\bar{z}}\right)^{3}=\left(\frac{1+\mathrm{z}}{1+\frac{1}{\mathrm{x}}}\right)^{3}=\mathrm{z}^{3}$

    \[ \left(\mathrm{i}\left(\cos \frac{2 \pi}{9}-\mathrm{i} \sin \frac{2 \pi}{9}\right)\right)^{3}=-\mathrm{i}\left(\cos \frac{2 \pi}{3}-\mathrm{i} \sin \frac{2 \pi}{3}\right)=-\mathrm{i}\left(-\frac{1}{2}-\mathrm{i} \frac{\sqrt{3}}{2}\right) \Rightarrow-\frac{1}{2}(\sqrt{3}-\mathrm{i}) \]
    #11837
    Om Sharma
    Keymaster

    Answer

    B

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