Topic 2 Complex Number JEE MAIN 2025
Viewing 7 topics - 1 through 7 (of 7 total)
-
- Topic
- Voices
- Last Post
-
-
Let the curve $\mathrm{z}(1+\mathrm{i})+\overline{\mathrm{z}}(1-\mathrm{i})=4, \mathrm{z} \in \mathrm{C}$, divide the region $|\mathrm{z}-3| \leq 1$ into two parts of areas $\alpha$ and $\beta$. Then $|\alpha-\beta|$ equals
Started by:
in: Jee Mains
- 1
- 1 week, 2 days ago
-
Let $\left|\frac{\bar{z}-\mathrm{i}}{2 \bar{z}+\mathrm{i}}\right|=\frac{1}{3}, \mathrm{z} \in \mathrm{C}$, be the equation of a circle with center at C. If the area of the triangle, whose vertices are at the points (0, 0), C and $(\alpha, 0)$ is 11 square units, then $\alpha^{2}$ equals
Started by:
- 1
- 1 week, 2 days ago
-
Let O be the origin, the point A be $\mathrm{z}_{1}=\sqrt{3}+2 \sqrt{2} \mathrm{i}$, the point $\mathrm{B}\left(\mathrm{z}_{2}\right)$ be such that $\sqrt{3}\left|\mathrm{z}_{2}\right|=\left|\mathrm{z}_{1}\right|$ and $\arg \left(\mathrm{z}_{2}\right)=\arg \left(\mathrm{z}_{1}\right)+\frac{\pi}{6}$. Then
Started by:
- 1
- 1 week, 2 days ago
-
Let $\left|\mathrm{z}_{1}-8-2 \mathrm{i}\right| \leq 1$ and $\left|\mathrm{z}_{2}-2+6 \mathrm{i}\right| \leq 2, \mathrm{z}_{1}, \mathrm{z}_{2} \in \mathrm{C}$. Then the minimum value of $\left|\mathrm{z}_{1}-\mathrm{z}_{2}\right|$ is
Started by:
- 1
- 1 week, 2 days ago
-
If the locus of $\mathrm{z} \in \mathrm{C}$, such that $\operatorname{Re}\left(\frac{\mathrm{z}-1}{2 \mathrm{z}+\mathrm{i}}\right)+\operatorname{Re}\left(\frac{\overline{\mathrm{z}}-1}{2 \overline{\mathrm{z}}-\mathrm{i}}\right)=2$, is a circle of radius r and center (a,b), then $\frac{15 \mathrm{ab}}{\mathrm{r}^{2}}$ is equal to
Started by:
- 1
- 1 week, 2 days ago
-
Let z be a complex number such that $|\mathrm{z}|=1$. If $\frac{2+\mathrm{k}^{2} \mathrm{z}}{\mathrm{k}+\overline{\mathrm{z}}}=\mathrm{kz}, \mathrm{k} \in \mathrm{R}$, then the maximum distance of $\mathrm{k}+\mathrm{ik}^{2}$ from the circle $|\mathrm{z}-(1+2 \mathrm{i})|=1$ is
Started by:
- 1
- 1 week, 2 days ago
-
Let the curve $\mathrm{z}(1+\mathrm{i})+\overline{\mathrm{z}}(1-\mathrm{i})=4, \mathrm{z} \in \mathrm{C}$, divide the region $|\mathrm{z}-3| \leq 1$ into two parts of areas $\alpha$ and $\beta$. Then $|\alpha-\beta|$ equals
Viewing 7 topics - 1 through 7 (of 7 total)
