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Question 28

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  • 7 October, 2026 at 11:17 pm #11817
    Om Sharma
    Keymaster

    The sum of all possible values of $\theta \in[-\pi, 2 \pi]$, for which $\frac{1+\mathrm{i} \cos \theta}{1-2 \mathrm{i} \cos \theta}$ is purely imaginary, is equal to [JEE (Main) 8 April 2024 S II]
    (A) $4 \pi$
    (B) $2 \pi$
    (C) $5 \pi$
    (D) $3 \pi$

    7 October, 2026 at 11:17 pm #11818
    Om Sharma
    Keymaster

    Solution

    $Z=\frac{(1+i \cos \theta)(1+2 i \cos \theta)}{(1-2 i \cos \theta)(1+2 i \cos \theta)} \Rightarrow Z=\frac{1-2 \cos ^{2} \theta+3 i \cos \theta}{1+4 \cos ^{2} \theta}$ is purely imaginary
    So, $\operatorname{Re}(\mathrm{Z})=0 \Rightarrow \frac{1-2 \cos ^{2} \theta}{1+4 \cos ^{2} \theta}=0 \Rightarrow \cos ^{2} \theta=\frac{1}{2} \Rightarrow \theta=-\frac{\pi}{4},-\frac{3 \pi}{4}, \frac{\pi}{4}, \frac{3 \pi}{4}, \frac{5 \pi}{4}, \frac{7 \pi}{4}$ sum of all solutions $=3 \pi$

    7 October, 2026 at 11:17 pm #11819
    Om Sharma
    Keymaster

    Answer

    D

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