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Two distinct numbers a and b are selected at random from
$1,2,3, \ldots \ldots, 50$. The probability, that their product ab is divisible by 3 , is
[JEE MAIN 22 Jan 2026 S I]
(1) $\frac{561}{1225}$
(2) $\frac{664}{1225}$
(3) $\frac{272}{1225}$
(4) $\frac{8}{25}$
First Method:
$\mathrm{P}(\mathrm{ab}$ is divisible by 3$)$
$=\mathrm{P}(\mathrm{a} \& \mathrm{~b}$ both are multiple of 3$)+\mathrm{P}($ Exactly are of $\mathrm{a} \& \mathrm{~b}$ is multiple of 3$)$
$=\frac{{ }^{16} \mathrm{C}_{2}}{{ }^{50} \mathrm{C}_{2}}+\frac{{ }^{16} \mathrm{C}_{1} \times{ }^{34} \mathrm{C}_{1}}{{ }^{50} \mathrm{C}_{2}}=\frac{8.15+16.34}{25(49)}=\frac{664}{1225}$
$3 \mathrm{~K}=\{3,6,9, \ldots, 48\}$
Second Method:
Number which are not multiple of $3=50-16=34$
$\mathrm{P}(\mathrm{ab}$ is divisible by 3$)=1-\mathrm{P}(\mathrm{ab}$ is not divisible by 3$)$
$=1-\frac{{ }^{34} \mathrm{C}_{2}}{{ }^{50} \mathrm{C}_{2}}=1-\frac{17 \times 93}{25 \times 49}=\frac{1225-561}{1225}=\frac{664}{1225}$ Answer(2)