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Question 35 — JEE Main 23 Jan 2026 S Ii

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  • #1097
    shahkb4
    Keymaster

    The number of ways, in which 16 oranges can be distributed to four children such that each child gets at least one orange, is
    [JEE MAIN 23 Jan 2026 S II]
    (1) 429
    (2) 384
    (3) 403
    (4) 455

    #1098
    shahkb4
    Keymaster

    Solution

    assuming all oranges are identical
    Let children $\mathrm{C}_{1}, \mathrm{C}_{2}, \mathrm{C}_{3}, \mathrm{C}_{4}$ get number of oranges $\mathrm{x}_{1}, \mathrm{x}_{2}, \mathrm{x}_{3}, \mathrm{x}_{4}$
    $\mathrm{x}_{1}+\mathrm{x}_{2}+\mathrm{x}_{3}+\mathrm{x}_{4}=16$ where $\mathrm{x}_{1}, \mathrm{x}_{2}, \mathrm{x}_{3}, \mathrm{x}_{4} \geq 1$
    let $\mathrm{x}_{\mathrm{i}}=\mathrm{x}_{\mathrm{i}}^{\prime}+1 ; \mathrm{x}_{1}^{\prime}+\mathrm{x}_{2}^{\prime}+\mathrm{x}_{3}^{\prime}+\mathrm{x}_{4}^{\prime}=12$
    Number of non-negative integral solutions ${ }^{n+p-1} C_{p-1}={ }^{12+4-1} C_{4-1}$
    $={ }^{15} \mathrm{C}_{3}=455$ Answer(4)

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